chitagong 12th bdmo
Posted: Thu Dec 11, 2014 6:03 pm
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chitagong 12th bdmo
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ABCD and EFGH are both squares with side length 4 units and DE=CE.AG=?
Re: chitagong 12th bdmo
Posted: Thu Dec 11, 2014 7:36 pm
Extend $AD$ and $GF$.Suppose,they meet at point $I$.
Now,$GI=6$,$AI=8$.$\therefore$ $AG=\sqrt{6^{2}+8^{2}}=10$
Now,$GI=6$,$AI=8$.$\therefore$ $AG=\sqrt{6^{2}+8^{2}}=10$