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A Problem
Posted: Tue Jan 25, 2011 7:37 pm
by Sudip Deb
x + 1/x = 6 . Find x .
Re: A Problem
Posted: Tue Jan 25, 2011 9:21 pm
by leonardo shawon
$x^2-6x+1=0$
\[x=\frac{6\pm\sqrt(32)}{2}\]
Re: A Problem
Posted: Wed Jan 26, 2011 1:50 pm
by Sudip Deb new
I can't understad ur answar . May be it is not the answar
Re: A Problem
Posted: Wed Dec 07, 2011 11:00 pm
by bristy1588
Sudip Deb, No, Leonardo's ans is correct
Re: A Problem
Posted: Thu Dec 08, 2011 9:07 pm
by Abdul Muntakim Rafi
\[ax^2+bx+c=0\]
\[x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\]
Sudip deb, Leonardo used this formula...