## BdMO regional 2018 set 4 Secondary P 06

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samiul_samin
Posts: 1007
Joined: Sat Dec 09, 2017 1:32 pm

### BdMO regional 2018 set 4 Secondary P 06

\$ABCD\$ is a quadrilateral, where \$BC=CD=2\$ and \$\angle DCA=\angle DBA\$,
\$\angle
BAC=60^{\circ}\$ . What is the length of \$BD\$?

Tasnood
Posts: 73
Joined: Tue Jan 06, 2015 1:46 pm

### Re: BdMO regional 2018 set 4 Secondary P 06

\$\angle DCA=\angle DBA\$
\$\angle BAC=\angle BDC=60^{\circ}\$
So, \$\triangle BDC\$ is isosceles and \$BD=2\$

samiul_samin
Posts: 1007
Joined: Sat Dec 09, 2017 1:32 pm

### Re: BdMO regional 2018 set 4 Secondary P 06

Tasnood wrote:
Thu Jan 17, 2019 5:32 pm
\$\angle DCA=\angle DBA\$