Mymensingh higher secondary 2013#8
Posted: Mon Feb 18, 2019 12:58 am
$ABCD$ is a trapezium with $AB\parallel CD$ and $\angle{ADC}=90^{\circ}$ . $E$ is a point on $CD$ that $BE\perp CD$. $F$ is a point on the extension of $CB$ that $DF\perp CF$.$DF$ and $EB$ intersects at the point $K$.$\angle {EAB}=47^{\circ}$,then$\angle {KCE}=$?