$2x^2-8x+7=x^2-2*4*x+4^2+x^2-9=(x-2)^2+(x+3)*(x-3)$
lowest value $(-5)$
Problems on Number Theory and Alzebra (frm BdMO)
Forum rules
Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
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AntiviruShahriar
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Re: Problems on Number Theory and Alzebra (frm BdMO)
If 'a' and 'b' is natural number hoi tahola qestion 4 ar choto somadhan ache. 3^a - 1=7^b . but, 3^a - 1 is divide by 2, and 7^b is not divided by 2.
Am i right?
Am i right?
You spin my head right round right round,
When you go down, when you go down down......(-$from$ "$THE$ $UGLY$ $TRUTH$" )
When you go down, when you go down down......(-$from$ "$THE$ $UGLY$ $TRUTH$" )
Re: Problems on Number Theory and Alzebra (frm BdMO)
@Rakeen, almost all the problems of this post are/have been re-posts. You have been warned several times. Please try to avoid re posts from now on, these activities make the forum clumsy. From now on I'll probably delete reposts.
"Je le vois, mais je ne le crois pas!" - Georg Ferdinand Ludwig Philipp Cantor
Re: Problems on Number Theory and Alzebra (frm BdMO)
Avik Roy wrote:@Rakeen, almost all the problems of this post are/have been re-posts. You have been warned several times. Please try to avoid re posts from now on, these activities make the forum clumsy. From now on I'll probably delete reposts.
sorry, I was also kinda lost here. But I think every thing is alright now, as I'm easy with this site. And please do delete the extra posts as it will help me also.
r@k€€/|/