## [OGC1] Online Geometry Camp: Day 2

Discussion on Bangladesh National Math Camp
Tusher Chakraborty
Posts: 27
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### Re: [OGC1] Online Geometry Camp: Day 2

Ayantika rinti bose wrote:Hello,
Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.

By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.

that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!
"Your present circumstances don't determine where you can go; they merely determine where you start." -Nido Qubein

*Mahi*
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### Re: [OGC1] Online Geometry Camp: Day 2

Tusher Chakraborty wrote:
Ayantika rinti bose wrote:Hello,
Actually i am not so sure if you are seeing my solutions or not because you are not replying to me.i was ill so i joined the camp 2 days later,but i have done all the maths from day 1 and also replied 2 you.please atleast send me an email that you are seeing my solutions.and here is the half solution of problem 1 day2.‘half ’ because that is what i could do.

By angle bisector theorem we find that BD/DC=AB/AC.so,AB/DC =root 41/root 164=1/2.so,2BD=DC.

that’s that i could do.BUT PLZ NOTIFY ME IF YOU ARE SEEING MY SOLUTIONS!!!!!
I think they are in different topics. Here are the total 4 posts you made - http://www.matholympiad.org.bd/forum/se ... 6&sr=posts . Did you make any other post than these?

Use \$L^AT_EX\$, It makes our work a lot easier!