so big series

For students of class 6-8 (age 12 to 14)
Zahin Hasin Rudro
Posts:11
Joined:Sun Jul 12, 2015 3:52 am
so big series

Unread post by Zahin Hasin Rudro » Wed Jul 15, 2015 2:26 pm

A new series is to be created after erasing some numbers from the series 1, 2, 3,
4…………. 400, in such a way so that the sum of any two numbers from the series
are not divisible by 7. What is the maximum number of terms to be found in new
series?

source:2014 dhaka ancholik, junior

Ittesaf_Ithun
Posts:1
Joined:Thu Dec 10, 2015 9:05 pm

Re: so big series

Unread post by Ittesaf_Ithun » Sat Dec 26, 2015 6:22 pm

bhai jan the ans will be probably 2....... :D :lol: :lol: :x :x :x :x :twisted: :twisted: :twisted:
from iftehazyeasir

thczarif
Posts:21
Joined:Mon Sep 25, 2017 11:27 pm
Location:Dhaka,Bangladesh

Re: so big series

Unread post by thczarif » Wed Dec 20, 2017 3:16 pm

We can divide all the numbers in 7 parts as (mod 7),7n,7n+1,7n+2,7n+3,7n+4,7n+5,7n+6.
now see, 7n+1+7n+6=14n+7,7n+2+7n+5=14n+7 and 7n+3+7n+4=14n+7.so if we take those number which are 1(mod 7) we cannot take those which are 6(mod 7) and so on.
there are floor of (400-1)/7 or 57 numbers from 1 to 400 which are 1 (mod 7)
floor of (400-2)/7 or 56 numbers of 2(mod 7)
floor of (400-3)/7 or 56 numbers of 3 (mod 7). But see if we take a number which is 0 (mod 7) there is no number which can make a sum divisible by 7.so total =57+56+56+1=170.

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