BDMO National Primary 2018/8
- nahin munkar
- Posts:81
- Joined:Mon Aug 17, 2015 6:51 pm
- Location:banasree,dhaka
From $1$ to $6$ nodes, one can go only right side and downward. From $7$ to $11$ nodes, one can go right side or along the diagonal. If you start from $1$, in how many ways can you reach $12$ ?
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# Mathematicians stand on each other's shoulders. ~ Carl Friedrich Gauss
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Re: BDMO National Primary 2018/8
Short answer
If I am not making any mistake. ![Embarrassed :oops:](./images/smilies/icon_redface.gif)
![Embarrassed :oops:](./images/smilies/icon_redface.gif)
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Re: BDMO National Primary 2018/8
it is not needed to go all the upper nodes.....so maybe the answer will not be 64
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Re: BDMO National Primary 2018/8
আয়তটির দৈর্ঘ্য, প্রস্থ বরাবর বিবেচনা করলে দুটি রাস্তা আছে। 1>7>12 & 1>6>12. প্রস্থ দুটিকে বাদ দিলে মোট 9টি খাড়া & বাকা রেখা আছে। এক্ষেত্রে 1×9×1=9. এখন 2+9=11. এটা আমার ধারনা। কদিন আগেই সম্ভাবনা শিখলাম তো তাই ![Mr. Green :mrgreen:](./images/smilies/icon_mrgreen.gif)
![Mr. Green :mrgreen:](./images/smilies/icon_mrgreen.gif)
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Re: BDMO National Primary 2018/8
There is no probablity here and I think there is a bug in your solution.
Re: BDMO National Primary 2018/8
Actually, I didn't solve it. I have used my দর্শনশক্তি। According the question I still think it will be 11.
Wãlkîñg, lõvǐñg, $mīlïñg @nd lìvíñg thě Lîfè