BdMO National Primary 2015#4

Discussion on Bangladesh Mathematical Olympiad (BdMO) National
samiul_samin
Posts:1007
Joined:Sat Dec 09, 2017 1:32 pm
BdMO National Primary 2015#4

Unread post by samiul_samin » Tue Feb 19, 2019 10:30 am

A circus party has the same number of lions as tigers. You asked to the owner of the circus the number of lions and tigers. He gave you the following information:
(i) An elephant is enough to feed all the tigers and lions in the circus.
(ii) Eighteen deers produce the same amount of meat as an elephant does.
(iii) A lion eats twice as much as a tiger.
(iv) One buffalo is enough to feed a lion and a tiger.
(v) A tiger will eat exactly the same amount of meat a deer has.
Find the number of tigers and lions in that circus party.

samiul_samin
Posts:1007
Joined:Sat Dec 09, 2017 1:32 pm

Re: BdMO National Primary 2015#4

Unread post by samiul_samin » Fri Feb 22, 2019 11:24 am

Hint
$(iv)$ is unnecessary to get the answer.
Answer
$6$
Solution
Number of lions=Number of tigers
According to the question,
$2$×Number of Tigers+Number of tiger =$18$
So, Number of Lions=Number of tigers=$6$

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