## 3 problems of probability

For students of class 11-12 (age 16+)
Abdul Muntakim Rafi
Posts: 173
Joined: Tue Mar 29, 2011 10:07 pm

### Re: 3 problems of probability

According to the given info, Tiham's answer is correct...
And probability of aiming something perfectly $9/10$ doesn't mean that if u will shoot the target the 9 out of 10 times... We can only say numbers of hitting the target will be near 9... And as much as you aim for the target($n$) the number of times you hit the target will be near $(9/10)*n$
Man himself is the master of his fate...

jhal_muri
Posts: 6
Joined: Sun Sep 11, 2011 1:58 am

### Re: 3 problems of probability

the results do not depend on previous results anyway.if u toss 2 coins and the first one gives a tail,then there is still 50/ chance for the 2nd coin to give a head as it is not effected.

nafistiham
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### Re: 3 problems of probability

yap, that's right.because that coin has two sides.
like that, if you wanna count the percentage of passing you can say one can have $1-100$ marks. he will pass if he gets at least $33$.so the probability will be $\frac {33}{100}$
but, saying that, there is many things which you can not defind by sides or marks.on that case you have to depend on the previous happenings

this is not correct.see the next post for correction
Last edited by nafistiham on Sun Dec 11, 2011 9:17 pm, edited 1 time in total.
$\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0$
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.

amlansaha
Posts: 100
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### Re: 3 problems of probability

Tiham, passing percentage is $\frac{68}{101}$, cause there are 101 numbers(0-100) u can get and 68 numbers(33-100) which will make u pass. so ans to ques no. 1 is $\frac{68}{101}$
Last edited by amlansaha on Sun Dec 11, 2011 9:26 pm, edited 1 time in total.
অম্লান সাহা

nafistiham
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### Re: 3 problems of probability

got the opposite one.silly mistake
$\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0$
Using $L^AT_EX$ and following the rules of the forum are very easy but really important, too.Please co-operate.

Mathlomaniac
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### Re: 3 problems of probability

Answer of first and second would be 11/12