Dhaka Secondary 2009/4
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Please don't post problems (by starting a topic) in the "Secondary: Solved" forum. This forum is only for showcasing the problems for the convenience of the users. You can post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Please don't post problems (by starting a topic) in the "Secondary: Solved" forum. This forum is only for showcasing the problems for the convenience of the users. You can post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
Dhaka Secondary 2009/4
\[( 1\frac{1}{2^2} ) ( 1 \frac{1}{3^2} ) ( 1 \frac{1}{4^2} ) ( 1 \frac{1}{5^2} ) (1 \frac{1}{6^2} ) \cdots (1 \frac{1}{1000^2} ) =?\]
Re: Dhaka Secondary 2009/4
Nice problem ..
Every logical solution to a problem has its own beauty.
(Important: Please make sure that you have read about the Rules, Posting Permissions and Forum Language)
(Important: Please make sure that you have read about the Rules, Posting Permissions and Forum Language)
Re: Dhaka Secondary 2009/4
I found a sequence out of the serial multiplications, my result is $\frac{1001}{2000}$
I just observed the multiplications of first 7 numbers, please check it though
I just observed the multiplications of first 7 numbers, please check it though

 Posts: 13
 Joined: Mon Aug 05, 2013 8:01 pm
Re: Dhaka Secondary 2009/4
What sequence did you find?