Rajshahi Higher Secondary 2017 P2

Forum rules
Please don't post problems (by starting a topic) in the "X: Solved" forums. Those forums are only for showcasing the problems for the convenience of the users. You can always post the problems in the main Divisional Math Olympiad forum. Later we shall move that topic with proper formatting, and post in the resource section.
samiul_samin
Posts: 1007
Joined: Sat Dec 09, 2017 1:32 pm

Rajshahi Higher Secondary 2017 P2

HABIZABI is a function that tells power of \$2\$ for any number. If the number is not a power of \$2\$, then it answers \$2\$. ABOLTABOL is a function which adds \$31\$ with a number and then HABIZABI it. HABIZABI(HABIZABI(ABOLTABOL(ABOLTABOL(\$2017\$ ))))=?

SA'AD
Posts: 5
Joined: Wed Jan 16, 2019 10:17 pm

Re: Rajshahi Higher Secondary 2017 P2

ABOLTABOL(2017) is equals to HABIZABI(2048) or HABIZABI(2^11) which is equals to 11
So ABOLTABOL(ABOLTABOL(2017))=ABOLTABOL(11)
Now,
ABOLTABOL(11)=HABIZABI(42) which is =2 [Since 42 is not a power of 2]
So, the question can be simplified as..
HABIZABI(HABIZABI(2^1))
=HABIZABI(1)
=HABIZABI(2^0)
=0 [ANS]
Be a good person but don't waste time to prove it..