Twin prime are infinite.
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Twin prime are infinite .
Let, prime number is limited and twin prime are also limited.
Now the largest twin prime are P1 & P2.
Now we can make
P = 2×3×5×7×11×13×17×19×… … … … … ×P1×P2
again let P3 & P4
which are made by
P3= P-1 &
P4= p+1
P3 & P4 both are prime number.
And P4= P3+2
So they are twin prime.
Now we can say that prime number & twin prime are infinity.
Let, prime number is limited and twin prime are also limited.
Now the largest twin prime are P1 & P2.
Now we can make
P = 2×3×5×7×11×13×17×19×… … … … … ×P1×P2
again let P3 & P4
which are made by
P3= P-1 &
P4= p+1
P3 & P4 both are prime number.
And P4= P3+2
So they are twin prime.
Now we can say that prime number & twin prime are infinity.
- nafistiham
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Re: Twin prine are infinite.
How are you sure that $P_3$ and $P_4$ are prime.It is true that all the primes till $P_2$ do not divide them.But, that does not mean they are primes.A larger prime may divide them.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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- Phlembac Adib Hasan
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Re: Twin prine are infinite.
The same mistake that I made three years ago while in class six.
Example:$2.3.5.7.11+1=30031$ is not dividable by any of $2,3,5,7,11$.But,however, it is dividable by larger prime $59$ as $30031=59*509$.
Example:$2.3.5.7.11+1=30031$ is not dividable by any of $2,3,5,7,11$.But,however, it is dividable by larger prime $59$ as $30031=59*509$.
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- nafistiham
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Re: Twin prine are infinite.
আমি জানি না যে কঞ্জেকচারটা কিভাবে প্রমান করা যায় । কিন্তু বলাই বাহুল্য যদি এটা এতই সোজা হতো, নিশ্চয়ই এতদিনে প্রমানিত হয়ে যেত ।
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: Twin prine are infinite.
Do you read "Nurone Abaro Anuranon" ?nafistiham wrote:How are you sure that $P_3$ and $P_4$ are prime.It is true that all the primes till $P_2$ do not divide them.But, that does not mean they are primes.A larger prime may divide them.
Are u know about Euclid's theory about Prime Numbers are infinite ?
- Phlembac Adib Hasan
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Re: Twin prine are infinite.
Not only you, many ''young mathematicians'' have made this mistake.(According to Md. Jafar Iqbal's 'তোমাদের প্রশ্ন আমার উত্তর')Euclid's proof has a second part.(It was not given in "Nurone Abaro Anuranon" for the sake of simplification)Bapy Biswas wrote:Do you read "Nurone Abaro Anuranon" ?nafistiham wrote:How are you sure that $P_3$ and $P_4$ are prime.It is true that all the primes till $P_2$ do not divide them.But, that does not mean they are primes.A larger prime may divide them.
Are u know about Euclid's theory about Prime Numbers are infinite ?
This proof does not find a larger prime.Only confirms us that there exists such one.Notice that if $P_3$ and $P_4$ are not primes, Euclid's proof still works.Because then they must be composite.But they are dividable by none of all primes that we defined.So they must be dividable by a larger prime (let $P_m$) than our defined largest prime.Hence there exists a larger prime $P_m$ than our defined prime.But the existence of $P_m$ breaks your proof.
And an off topic mater : Tiham vaia is one of the most senior and genius campers.So you should think before saying he did not read kidding books like "Nurone Abaro Anuranon".
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- nafistiham
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Re: Twin prine are infinite.
ভাই, আমারে এত্ত সিনিয়র বানায়ও না ।Phlembac Adib Hasan wrote:
And an off topic mater : Tiham vaia is one of the most senior and genius campers.So you should think before saying he did not read kidding books like "Nurone Abaro Anuranon".
আর নিউরনে আবারো অনুরণন কোন kidding book না ।
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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Re: Twin prine are infinite.
2*3*5*7*11*13+1=30031=59*509.
so, is 30031 a prime ?
so, is 30031 a prime ?
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Re: Twin prine are infinite.
এই ভুলটা আমিও করেছিলাম ।। সবাই জাফর ইকবাল স্যারের " তোমাদের প্রশ্ন , আমার উত্তর " বইটা পড়ে দেখ, স্যার বইটার শেষের দিকে বিষয়টা খুব সুন্দর করে বুঝিয়ে দিয়েছেন ।
- nafistiham
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Re: Twin prine are infinite.
আর একই সাথে এটাও প্রমানিত যে কোনভাবেই এমন বহুপদী বানানো সম্ভব না যেটা দিয়ে নিশ্চিতভাবে মৌলিক সংখ্যা পাওয়া যায় ।
Last edited by nafistiham on Fri Mar 09, 2012 8:50 pm, edited 1 time in total.
\[\sum_{k=0}^{n-1}e^{\frac{2 \pi i k}{n}}=0\]
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